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1. The length of a immaterial box is 2 units sparse than its width. If the area of the box is 15 units square. Find the perimeter of the box.   B. 16(Correct Answer)  definition These are the formulas for the box. A= L x W P = 2( L + W) We know that the area is 15 15= L x W Also, L= W-2 Now we bathroom practice both formulas (W)(W-2) = 15 W² - 2W= 15 W²- 2W-15= 0 (W-5) (W+3) = 0 W= 5 , W= -3 We so-and-so digit the Length, L = W-2 = 5- 2= 3 L= 3 Finally the perimeter: P = 2( 3+ 5) P = 2(8) P= 16 2. Evaluate the avocation fashion if X=-2, Y= 3, Z= -5 2X²-3Y-3Z   D. 14(Correct Answer)  accounting 2(-2)² -3(3) -3(-5) = 2(4) -9 +15 = 8-9 +15= 14 3. Simplify:   C.  (Correct Answer)   write up You exact to simplify one after another exponent, since you are dealing with a square root you destiny to rewrite the exponents as level exponents. a³ = a²a b?= b?b Z³ =Z²Z Now you can divide the exponents by cardinal: ab³Z and the residual wheel has to be deep down the square root ?(abZ) 4. procreate: (3X -5)(2X+ 5)    5. act: 3(5X-1)<4(X-6)  commentary 3(5X-1)<4(X-6) 15X-3 < 4X -24 15X-4X < -24 + 3 11X < -21 X< -21/11 6.

Solve for X: 3(X-5)-4X = 6(X-10) -(X+ 5)   account 3X -15 -4X= 6X -60 -X- 5 -X -15= 5X -65 -6X= -65 +15 -6X= -50 X= -50/-6 = 25/3 7. Translate the pursuance blame into an algebraic expression: The product of a pasture and half dozen is triad times the same subject less(prenominal) than ex write up The product message propagation: 6 and X is means enough sign = three times the same number less than ten 10 -3X 8. Simplify: -3(p-5p²) + 3p²-6P  Explanation -3p + 15p²+ 3p²-6p= 18p²-9p   9. Which of the following equations passes through signalise  (-3,-16) 10. ------------------------------------------------- Top of Form 11. Bottom of Form Explanation Substituting the determine in all the equations we run low that the resolve is Y= 2X-10...If you emergency to get a full essay, battle array it on our website: Orderessay

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